Weighting a Fish - Here are a couple of ideas (all from students) ....

  1. A simple scale ... which is like a lever.  If 10 pounds on the other side balances the scale, your fish weighs 10 pounds too.  Daaa!  Likewise, you could use a single pulley and string with some weights. You hang the pulley, then you hang the fish on side, and you slowly add weights to the other side till the fish and the weights are equal. Then you will know actually how much the fish weighs.
     
  2. How about placing the fish on a piezoelectric crystal?  The more it weighs, the more stress on the crystal .. the greater the voltage ... which is picked up on a digital display.
     
  3. Let our fish dangle from a piezo-resistive wire.  That is, as the stress in the wire changes, so does the electrical resistance in the wire ... which is picked up by a microchip.
     
  4. Have a board of cork free floating atop water and set the fish on this board. The water level will rise as the water is displaced and can be measured by markers on the side of the tray of water that the cork board is set in.

    This would only give you the volume of displaced water but it is a very good start (and worth full credit here).  Have you heard of Archimedes' principle?  It says that the weight of the displaced water is equal to the "buoyant force".  If you want to weigh a boat, you could put it in a brim full bath tub (the tub might have to be pretty big) and let water overflow.  Now weigh the overflow water and you have weighed the boat.  This is essentially what you have done here – only don’t just measure the displacement height … find the weight of the displaced water instead.  Remember that the number you get is the fish plus the cork slab so take that into account by subtracting it in the end to get the fish weight alone. 

    Jim
     

  5. Get a transparent cylindrical container of known diameter. Fill it about half way and mark the level of the water. Drop the fish into the water and then measure how much the water level has moved up from the mark. From this you can calculate the volume of water displaced (at 8 lbs/gal) and you'd know how much the fish weighs.

    This is assuming they both have the same density.  For example, if the fish were made of lead, it wouldn't work without a correction factor.  However, I think you can assume the fish is about the same density as water.

    Jim
     

  6. I know we weren't suppose to use the Internet but I found this interesting.  I found that you could find the weight of a fish by applying simple math by measuring the fish from tip of its nose to fork of the tail then around the fish in the front of the pectoral fins (girth).  Now if you take the girth measurement (the circumference around the fish taken in the front of the pectoral fins measured in inches) and square it, then multiply this by the length measurement (again in inches) and divide the product by 800 you will come out with the weight of the fish in pounds.

    Okay maybe it isn't simple math but it does work.

    Way harder and more complicated then the scale, but it works.
     
  7. OK, HOW ABOUT THIS. YOU WEIGHT YOURSELF ON A WEIGHING SCALE, THEN WEIGHT YOURSELF WHILE HOLDING THE FISH. AFTERWARDS, JUST SUBTRACT THE AMOUNT YOU WEIGHED ALONE, TO THE AMOUNT YOU WEIGHED WITH THE FISH. I'M PRETTY SURE THIS WOULD WORK ACCURATELY.

    OK .. a bit lame but you know, this is exactly how I ended up weighing my bike and a bike rack (to see if I've exceeded a weight limit) ... so I'll take it.

    Jim

     
  8. Get a spring and set it on a desk then get a board and put this fish on top of the "spring board".  The spring will compress more or less depending upon the weight of the fish. (In your example you relied on spring expansion, not compression). 

    One must be sure the spring is not fully compressed or you won't get a true reading.
     

  9. In a capacitor, if the plates change their distance with respect to each other then the voltage changes as well. OK, so you could somehow hang your fish from a string but put a capacitor in between so the weight of the fish could pull the plates apart slightly.  The heavier the fish, the more the plates would be pulled apart.  I suppose you would have to calibrate this with known weights first but after that it should give an accurate reading.

    Super answer xxxx.  Too bad you didn't think of this earlier because, in fact, this has already been thought of.  It is called a capacitive sensor.  One plate is held fixed and the applied force is able to move the other plate (just as you said).  Good job!

    Jim

     
  10. This might make the fish mad but you could apply a known force to your fish and measure the acceleration you get as a result.  Since  Newton's laws would apply here, you could derive the mass of the fish from the equation F = ma.  You would know F and "a", then solve for "m" which is the mass of the fish.

    I can see you took a physics class.  You found a great solution (and don't worry, the fish is already dead).  Now I'll bet you didn't know that this is exactly how they "weight" astronauts in space.  Your bathroom scale would be useless in orbit so they literally shake the poor space traveler in a chair.  Since they still have inertia, the amount of resistance their bodies offer to the apparatus, the more mass they have.  This chair is calibrated on the surface of the earth so you can match the machine results (which works anywhere) with their surface weight.

    Jim

     
  11. I'm not sure if you this would work but you could make an electromagnet and then keep adding more current which would make the magnetic field stronger.  Now you have to keep the hook in the fishes mouth because you would need something that would hold the fish to the magnet.  Now keep adding current until it's enough to support the weight of the fish (plus the hook).  Once it does, you should be able to read the current and calculate the weight.

    Yes, but it would be easier to just celebrate the apparatus with known weights first and then your idea is perfect.  You may need something more than just a small metal hook but that is all I have to add.

    Jim

     
  12. My fish scale would start with a rod that lends itself to bending without breaking, something like those rods that are used in a bowflex machine.  The rod would be held horizontally and the fish would be hung from the end of the rod. The weight of the fish would cause bending of the rod. Heavier fish would obviously cause more bending and lighter fish would cause less bending.

    The rod would have a top and a bottom.  A piezoresistive material would be built into the center lower part of the rod, at the point where a bending force would cause a compression of the material that makes up the rod. Battery supplied current would be sent through the piezoresistive material just before weighing. (the device would be turned on.) As the fish was hung from the cable, the rod would bend causing pressure to be applied to the piezoresistive material.  The electrical resistance of the piezoresistive material would change as pressure was applied to it.  The changes in the current (amperage) would be detected by the computer chip in the electronics of the scale and should be in proportion to the amount of bending.  The weight of the fish would be displayed on a digital display. 

    Super duper answer xxxxxxx

    Normally I'd tell you to go and patient but guess what ... already done (although maybe not for weighing fish).  The rod actually has two piezoelectric crystals (maybe for accuracy) ... one at the top where the rod is pulled apart (tension) and one at the bottom (where it gets compressed).   A piezoresistive crystal could be used but that is called an "active" sensor .. meaning an outside power source is required.  If you just use a piezoelectric crystal (which makes its own power .. which is called a passive sensor)  I guess it is a bit cheaper???  But there is even more to your post that I need to expand on.  You say the degree of deflection is an indicator of weight.  Correct!  In the case of a spring, the distortion is caused by a force "in line" with the spring (something related to stress) and the distortion is called
    strain.  In the case of an applied torque, it is called a shear stress and the resulting deformation is called a shear strain and you are 100% correct.  Within the elastic limit, the degree of bend is proportional to the weight of the fish.

    Jim